06: Logistic Regression

  • Where y is a discrete value
    • Develop the logistic regression algorithm to determine what class a new input should fall into
  • Classification problems
    • Email -> spam/not spam?
    • Online transactions -> fraudulent?
    • Tumor -> Malignant/benign
  • Variable in these problems is Y
    • Y is either 0 or 1
      • 0 = negative class (absence of something)
      • 1 = positive class (presence of something)
  • Start with binary class problems
    • Later look at multiclass classification problem, although this is just an extension of binary classification
  • How do we develop a classification algorithm?
    • Tumour size vs malignancy (0 or 1)
    • We could use linear regression
      • Then threshold the classifier output (i.e. anything over some value is yes, else no)
      • In our example below linear regression with thresholding seems to work

  • We can see above this does a reasonable job of stratifying the data points into one of two classes
    • But what if we had a single Yes with a very small tumour 
    • This would lead to classifying all the existing yeses as nos
  • Another issues with linear regression
    • We know Y is 0 or 1
    • Hypothesis can give values large than 1 or less than 0
  • So, logistic regression generates a value where is always either 0 or 1
    • Logistic regression is a classification algorithm - don't be confused
Hypothesis representation
  • What function is used to represent our hypothesis in classification
  • We want our classifier to output values between 0 and 1
    • When using linear regression we did hθ(x) = (θT x)
    • For classification hypothesis representation we do hθ(x) = g((θT x))
      • Where we define g(z)
        • z is a real number
      • g(z) = 1/(1 + e-z)
        • This is the sigmoid function, or the logistic function
      • If we combine these equations we can write out the hypothesis as
  • What does the sigmoid function look like
  • Crosses 0.5 at the origin, then flattens out]
    • Asymptotes at 0 and 1

  • Given this we need to fit θ to our data
Interpreting hypothesis output
  • When our hypothesis (hθ(x)) outputs a number, we treat that value as the estimated probability that y=1 on input x
    • Example
      • If X is a feature vector with x0 = 1 (as always) and x1 = tumourSize
      • hθ(x) = 0.7
        • Tells a patient they have a 70% chance of a tumor being malignant
    • We can write this using the following notation
      • hθ(x) = P(y=1|x ; θ)
    • What does this mean?
      • Probability that y=1, given x, parameterized by θ
  • Since this is a binary classification task we know y = 0 or 1
    • So the following must be true
      • P(y=1|x ; θ) + P(y=0|x ; θ) = 1
      • P(y=0|x ; θ) = 1 - P(y=1|x ; θ)

Decision boundary
  • Gives a better sense of what the hypothesis function is computing
  • Better understand of what the hypothesis function looks like
    • One way of using the sigmoid function is;
      • When the probability of y being 1 is greater than 0.5 then we can predict y = 1
      • Else we predict y = 0
    • When is it exactly that hθ(x) is greater than 0.5?
      • Look at sigmoid function
        • g(z) is greater than or equal to 0.5 when z is greater than or equal to 0

      • So if z is positive, g(z) is greater than 0.5
        • z = (θT x)
      • So when 
        • θT x >= 0 
        • 결국 위와 같을 때, 즉 Z가 0보다 크다면 0.5 이상의 값이 되어서 logistic regression은 이 때 1로 prediction을 하게 된다.
      • Then hθ >= 0.5
  • So what we've shown is that the hypothesis predicts y = 1 when θT x >= 0 
    • The corollary of that when θT x <= 0 then the hypothesis predicts y = 0 
    • Let's use this to better understand how the hypothesis makes its predictions
Decision boundary
  • 좀 더 디테일 하게 들어가 보자.
  • hθ(x) = g(θ0θ1xθ2x2)

  • 최종 적으로 학습을 통해서 hypethosis는 아래와 같은 weight vector를 가진다고 가정해 보자.
  • So, for example
    • θ0 = -3
    • θ1 = 1
    • θ2 = 1
  • So our parameter vector is a column vector with the above values
    • So, θT is a row vector = [-3,1,1]
  • What does this mean?
  • 결국 위의 예제와 같이 0을 기점으로 1과 0의 prediction이 결정 된다.
    • The z here becomes θT x
    • We predict "y = 1" if
      • -3x0 + 1x1 + 1x2 >= 0
      • -3 + x1 + x2 >= 0
  • We can also re-write this as
    • If (x1 + x2 >= 3) then we predict y = 1
    • If we plot
      • x1 + x2 = 3 we graphically plot our decision boundary

  • Means we have these two regions on the graph
    • Blue = false
    • Magenta = true
    • Line = decision boundary
      • Concretely, the straight line is the set of points where hθ(x) = 0.5 exactly
    • The decision boundary is a property of the hypothesis
      • Means we can create the boundary with the hypothesis and parameters without any data
        • Later, we use the data to determine the parameter values
      • i.e. y = 1 if
        • 5 - x1 > 0
        • 5 > x1
Non-linear decision boundaries
  • 비선 형에 대해서도 고차원 다항식을 통해서 decision boundary를 얻을 수 있다.
  • Get logistic regression to fit a complex non-linear data set
    • Like polynomial regress add higher order terms
    • So say we have
      • hθ(x) = g(θ0θ1x1θ3x12θ4x22)
      • We take the transpose of the θ vector times the input vector 
        • Say θT was [-1,0,0,1,1] then we say;
        • Predict that "y = 1" if
          • -1 + x12x22 >= 0
          • x12x22 >= 1 
        • If we plot x12x22 = 1 (원의 방정식)
          • This gives us a circle with a radius of 1 around 0

  • Mean we can build more complex decision boundaries by fitting complex parameters to this (relatively) simple hypothesis
  • More complex decision boundaries?
    • By using higher order polynomial terms, we can get even more complex decision boundaries

모든 다 할 수 있다. 복잡한 다항식을 이용 한다면,  

Cost function for logistic regression
  • Fit θ parameters
  • Define the optimization object for the cost function we use the fit the parameters
    • Training set of m training examples
      • Each example has is n+1 length column vector

  • This is the situation
    • Set of m training examples
    • Each example is a feature vector which is n+1 dimensional
    • x0 = 1
    • y ∈ {0,1}
    • Hypothesis is based on parameters (θ)
      • Given the training set how to we chose/fit θ?
  • Linear regression uses the following function to determine θ

  • Instead of writing the squared error term, we can write
    • If we define "cost()" as;
      • cost(hθ(xi), y) = 1/2(hθ(xi) - yi)2
      • Which evaluates to the cost for an individual example using the same measure as used in linear regression
    • We can redefine J(θ) as

      • Which, appropriately, is the sum of all the individual costs over the training data (i.e. the same as linear regression)

  • To further simplify it we can get rid of the superscripts
    • So
    • 위에서 정의한 Cost Function은 linear regression에서는 optimization 알고리즘인 gradient descent로 잘 동작 했지만, hypothesis function이 sigmoid로 바뀐다면 이것은 optimize가 잘 되지 않는 문제점이 있다.
    • 결국 다른 cost function의 구조를 찾아야 한다.
  • What does this actually mean?
    • This is the cost you want the learning algorithm to pay if the outcome is hθ(x) and the actual outcome is y
    • If we use this function for logistic regression this is a non-convex function for parameter optimization
      • Could work....
  • What do we mean by non convex?
    • We have some function - J(θ) - for determining the parameters
    • Our hypothesis function has a non-linearity (sigmoid function of hθ(x) )
      • This is a complicated non-linear function
    • If you take hθ(x) and plug it into the Cost() function, and them plug the Cost() function into J(θ) and plot J(θ) we find many local optimum -> non convex function
  • 만약 이상태로 gradient descent algorithm을 실행 한다면, global minimum으로 converge 되지 않는다.

    • Why is this a problem
      • Lots of local minima mean gradient descent may not find the global optimum - may get stuck in a global minimum
    • We would like a convex function so if you run gradient descent you converge to a global minimum
A convex logistic regression cost function
  • To get around this we need a different, convex Cost() function which means we can apply gradient descent

  • This is our logistic regression cost function
    • This is the penalty the algorithm pays
    • Plot the function
  • Plot y = 1
    • So hθ(x) evaluates as -log(hθ(x))

위 그래프가 우리가 원하는 cost function이다.
즉, y=1이고 prediction이 1이라면, -log (1)의 값은 0이다. 즉 penalty가 없다.
하지만 prediction이 0에 가까울 수록 -log(x)의 값은 커지므로 penalty 값이 증가하게 된다.

  • So when we're right, cost function is 0
    • Else it slowly increases cost function as we become "more" wrong
    • X axis is what we predict
    • Y axis is the cost associated with that prediction
  • This cost functions has some interesting properties
    • If y = 1 and hθ(x) = 1
      • If hypothesis predicts exactly 1 and thats exactly correct then that corresponds to 0 (exactly, not nearly 0)
    • As hθ(x) goes to 0
      • Cost goes to infinity
      • This captures the intuition that if hθ(x) = 0 (predict (y=1|x; θ) = 0) but y = 1 this will penalize the learning algorithm with a massive cost
  • What about if y = 0
  • then cost is evaluated as -log(1- hθ( x ))
    • Just get inverse of the other function

  • Now it goes to plus infinity as hθ(x) goes to 1
  • With our particular cost functions J(θ) is going to be convex and avoid local minimum
Simplified cost function and gradient descent
  • Define a simpler way to write the cost function and apply gradient descent to the logistic regression
    • By the end should be able to implement a fully functional logistic regression function
  • Logistic regression cost function is as follows

  • This is the cost for a single example
    • For binary classification problems y is always 0 or 1
      • Because of this, we can have a simpler way to write the cost function
        • Rather than writing cost function on two lines/two cases
        • Can compress them into one equation - more efficient 
    • Can write cost function is
      • cost(hθ, (x),y) = -ylog( hθ(x) ) - (1-y)log( 1- hθ(x) ) 
        • This equation is a more compact of the two cases above
    • We know that there are only two possible cases
      • y = 1
        • Then our equation simplifies to
          • -log(hθ(x)) - (0)log(1 - hθ(x))
            • -log(hθ(x))
            • Which is what we had before when y = 1
      • y = 0
        • Then our equation simplifies to
          • -(0)log(hθ(x)) - (1)log(1 - hθ(x))
          • = -log(1- hθ(x))
          • Which is what we had before when y = 0
      • Clever!
  • So, in summary, our cost function for the θ parameters can be defined as

이러한 convexity analysis는 수업의 scope를 넘어선다. 일단 위와 같은 cost function을 cross entropy라고도 부른다.

  • Why do we chose this function when other cost functions exist?
    • This cost function can be derived from statistics using the principle of maximum likelihood estimation
      • Note this does mean there's an underlying Gaussian assumption relating to the distribution of features 
    • Also has the nice property that it's convex
  • To fit parameters θ:
    • Find parameters θ which minimize J(θ)
    • This means we have a set of parameters to use in our model for future predictions
  • Then, if we're given some new example with set of features x, we can take the θ which we generated, and output our prediction using

    • This result is
      • p(y=1 | x ; θ)
        • Probability y = 1, given x, parameterized by θ
How to minimize the logistic regression cost function
  • Now we need to figure out how to minimize J(θ)
    • Use gradient descent as before
    • Repeatedly update each parameter using a learning rate

편미분에 의해서 구해진 식이다.

이해가 안된다면 이전 포스트 참조

  • If you had features, you would have an n+1 column vector for θ
  • This equation is the same as the linear regression rule
    • The only difference is that our definition for the hypothesis has changed
  • Previously, we spoke about how to monitor gradient descent to check it's working
    • Can do the same thing here for logistic regression
  • When implementing logistic regression with gradient descent, we have to update all the θ values (θ0 to θn) simultaneously
    • Could use a for loop
    • Better would be a vectorized implementation
  • Feature scaling for gradient descent for logistic regression also applies here

Advanced optimization
  • Previously we looked at gradient descent for minimizing the cost function
  • Here look at advanced concepts for minimizing the cost function for logistic regression
    • Good for large machine learning problems (e.g. huge feature set)
  • What is gradient descent actually doing?
    • We have some cost function J(θ), and we want to minimize it
    • We need to write code which can take θ as input and compute the following
      • J(θ)
      • Partial derivative if J(θ) with respect to j (where j=0 to j = n)

  • Given code that can do these two things
    • Gradient descent repeatedly does the following update

  • So update each j in θ sequentially
  • So, we must;
    • Supply code to compute J(θ) and the derivatives
    • Then plug these values into gradient descent
  • Alternatively, instead of gradient descent to minimize the cost function we could use
    • Conjugate gradient
    • BFGS (Broyden-Fletcher-Goldfarb-Shanno)
    • L-BFGS (Limited memory - BFGS)
  • These are more optimized algorithms which take that same input and minimize the cost function
  • These are very complicated algorithms
  • Some properties
    • Advantages
      • No need to manually pick alpha (learning rate)
        • Have a clever inner loop (line search algorithm) which tries a bunch of alpha values and picks a good one
      • Often faster than gradient descent
        • Do more than just pick a good learning rate
      • Can be used successfully without understanding their complexity
    • Disadvantages
      • Could make debugging more difficult
      • Should not be implemented themselves
      • Different libraries may use different implementations - may hit performance
Using advanced cost minimization algorithms
  • How to use algorithms
    • Say we have the following example

  • Example above
    • θ1 and θ2 (two parameters)
    • Cost function here is J(θ) = (θ1 - 5)2 + θ2 - 5)2
    • The derivatives of the J(θ) with respect to either θ1 and θ2 turns out to be the 2(θi - 5)
  • First we need to define our cost function, which should have the following signature
function [jval, gradent] = costFunction(THETA)
  • Input for the cost function is THETA, which is a vector of the θ parameters
  • Two return values from costFunction are
    • jval
      • How we compute the cost function θ (the underived cost function) 
        • In this case = (θ1 - 5)2 + (θ2 - 5)2
    • gradient
      • 2 by 1 vector
      • 2 elements are the two partial derivative terms
      • i.e. this is an n-dimensional vector
        • Each indexed value gives the partial derivatives for the partial derivative of J(θ) with respect to θi
        • Where i is the index position in the gradient vector 
  • With the cost function implemented, we can call the advanced algorithm using
options= optimset('GradObj', 'on', 'MaxIter', '100'); % define the options data structure
initialTheta= zeros(2,1); # set the initial dimensions for theta % initialize the theta values
[optTheta, funtionVal, exitFlag]= fminunc(@costFunction, initialTheta, options); % run the algorithm
  • Here
    • options is a data structure giving options for the algorithm
    • fminunc
      • function minimize the cost function (find minimum of unconstrained multivariable function)
    • @costFunction is a pointer to the costFunction function to be used
  • For the octave implementation
    • initialTheta must be a matrix of at least two dimensions 
  • How do we apply this to logistic regression?
    • Here we have a vector 

  • Here
    • theta is a n+1 dimensional column vector
    • Octave indexes from 1, not 0
  • Write a cost function which captures the cost function for logistic regression

Multiclass classification problems
  • Getting logistic regression for multiclass classification using one vs. all
  • Multiclass - more than yes or no (1 or 0)
    • Classification with multiple classes for assignment

  • Given a dataset with three classes, how do we get a learning algorithm to work?
    • Use one vs. all classification make binary classification work for multiclass classification
  • One vs. all classification
    • Split the training set into three separate binary classification problems
      • i.e. create a new fake training set
        • Triangle (1) vs crosses and squares (0) hθ1(x)
          • P(y=1 | x1θ)
        • Crosses (1) vs triangle and square (0) hθ2(x)
          • P(y=1 | x2θ)
        • Square (1) vs crosses and square (0) hθ3(x)
          • P(y=1 | x3θ)
Train a logistic regression classifier h_theta^(i) (x) for each class i 
to predict the probability that you = i .

On a new input x, to make a prediction, pick the class i that maximizes:

max h_\theta ^(i) (x)

  • Overall
    • Train a logistic regression classifier hθ(i)(x) for each class i to predict the probability that y = i
    • On a new input, x to make a prediction, pick the class i that maximizes the probability that hθ(i)(x) = 1 

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